Hey Guys Wonderfull opportunity for you.

Ready to make a reminder in Google calendar.

World looking for Artificial Intelligance Experinced Guys.

Why Not you?

NO Idea about AI .Dont worry here's were this event is Beginner Friendly only.

So. gain some knowelde by attending this event.


GCET is collabarated with SMARTBRIDG.

Geethanjali College of Engineering and Technology  is planning to conduct a 2 days work shop on  to Build  Artificial Intelligence  Application using IBM.

 for registration click here

----> No registration fee.

-----> Date 02-03 April

------> Timing : morning session(10.00AM-12.00PM)

              Afternoon Session    -  01.00PM-03.00PM

Coding Competition CODEX From Scaller Community


A Quick  Hi to everyone! 


We've got something special that we want you to block your calendar for and register on ASAP! Scaler brings to you CodeX - a pan-India coding challenge for software developers. It has something for everyone -

👉 High-quality practice

👉 Opportunity to learn & improve

👉 Exciting awards worth INR 70L+, bragging rights, and much more!




Go head-to-head with the best for some exciting prizes & opportunities in Competitive Mode or take your time, learn each question properly and improve in Learning Mode. You'll also get a personalized performance report to understand where you need to improve and how.


You can register yourself here -Click here - it barely takes a minute.


The contest starts on 9th April 8 PM & registrations are already open - so tell all your coder friends immediately !

Tricky for finding Combination of numbers by given r length

 #include<stdio.h>

void combo2(int [],int [],int ,int,int,int);

int main()

{

int k;

scanf("%d",&k);

int a[k];

int l=0;

 for(l=0;l<k;l++)

 {

  scanf("%d",&a[l]);

 }

int m;

scanf("%d",&m);

int data[m];

combo2(a,data,0,k-1,0,m);

return 0;

}

void combo2(int a[],int data[],int start,int end,int index,int r)

{

if(index==r)

{ int i;

for(i=0;i<r;i++)

{

printf("%d ",data[i]);

}

printf("\n");

}

else

{int k;

for(k=start;k<=end&& end-k+1>=r-index;k++)

{

data[index]=a[k];

combo2(a,data,k+1,end,index+1,r);

}

}

}


LFX Mentorship Applications are now open

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